You are watching: A 17.0 m high and 11.0 m long wall
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This is College Physics Answers through Shaun Dychko. There"s wind blowing on this wall and exerting a force of 650 newtons for every square mater of wall surconfront location so we have to calculate the location of this wall. We are told that it"s 11.0 meters long and also 17.0 meters high and so we"ll take that location of the length times the elevation I speak to the "w" for width however anymethod... you obtain the idea. So this measurement multiplied by the height multiplied by 650 is the total pressure exerted by the wind on the wall. So that"s 11.0 meters times 17.0 meters times 650 which is 1.2155 times 10 to the 5 newlots. We assume that this pressure is exerted in the middle of the wall so 8.50 meters over the ground however we are not actually going to usage that reality for anypoint below we are going to use the first condition of equilibrium which is to say that the complete horizontal forces have to include up to zero or you might say the total pressure to the left has to equal the total force to the appropriate and this below is the total force of all ten braces together perpendicular component. So this force is along the brace, we are told, and also we have the right to discover a component perpendicular to the wall and the component parallel to the wall; it"s the perpendicular one that we are interested in bereason that"s the one that hregarding balance the force exerted by the wind so F B perpendicular amounts to pressure of the wind. And this is the oppowebsite leg of this triangle and also so we must usage sin Θ multiplied by the hypotenusage to uncover F B perpendicular. So we have actually F B sin Θ equals force exerted by the wind and also divide both sides by sin Θ and also we resolve for the complete pressure of all ten braces. So that"s 1.2155 times 10 to the 5 newloads split by sin of 35 degrees bereason this Θ is opposite to this angle here and so these oppowebsite angles are equal and that"s 2.12 times 10 to the 5 newloads. Now the force exerted by a single brace is going to be that complete force separated by the 10 braces and also so 2.12 times to the 4 newlots is the pressure exerted by a single brace.
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