Specific heat means the heat to advanced the temperature of 1 gram that the product by 1 level C.

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So if you want to advanced the temperature of the one gram indigenous 19 to 35 degrees, that exact same gram will require #35-19=16# time as much heat.

And if you desire to advanced the temperature the 193 grams in stead of simply 1 gram, you will need 193 times as much heat.

These two combined give united state the adhering to equation:

#Q=c*m*DeltaT#

#c=#specific heat = because that one gram, one level differencemultiply by:#m=#mass, the lot of grams you desire to warm upmultiply again by:#DeltaT=#the temperature *rise* you wish

Your answer:#Q=c*m*DeltaT=2.46*193*(35-19)~~7596J#

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Stefan V.

Apr 1, 2015

You know the particular heat the ethanol, which represents the lot of heat required to rise the temperature the *1 gram* of ethanol by *1 level Celsius*.

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In other words, to get the temperature of 1 gram that ethanol to boost by 1 degree Celsius, you must supply **2.46 J** of power to it.

Now, you know the initial and also final temperature of the sample - #19^

"C"# and also #"35"^

"C"#; this means that the temperature of her ethanol sample enhanced by

#DeltaT = T_("final") - T_("initial") = 35 - 19 = 16^

"C"#

You need to supply enough energy to boost the temperature that the sample through #16^

"C"#, however you have to tak into account *how lot ethanol* you have, i.e. The fixed given.

The relationship between supplied energy (or heat), mass, and increase in temperature is given by

#q = m * c * DeltaT#, where

#q# - the quantity of power supplied;#m# - the massive of the problem - in your case, the fixed of ethanol;#c# - the specific heat of ethanol;#DeltaT# - the adjust in temperature;

To recognize *how lot energy* is required to heat **193 g** of ethanol through #16^

"C"#, plug her values into the above equation

#q = "193"cancel("g") * 2.46"J"/(cancel("g") * ^

cancel("C")) * 16^

cancel("C") = "7596.48 J"#

Rounded to 2 sig figs, the number of sig figs offered for 19 and 35 levels Celsius, the answer will certainly be

#q = color(green)("7600 J")#

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lining W.

Apr 1, 2015

The heat compelled is same to the mass of ethanol (193 g) multiply by the details heat capacity (2.46 J/g-C) times the preferred temperature difference (35 C - 19 C = 16 C):

#193 g time 2.46 J/(g-C) time 16C=7596 J#

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