ns am new to both python and also numpy.I ran a code that ns wrote and also I am acquiring this message:"index 0 is the end of bounds because that axis 0 with size 0"Without the context, I simply want to number out what this means.. It can be silly to questioning this but what execute they median by axis 0 and also size 0? table of contents 0 method the very first value in the array.. Yet I can"t figure out what axis 0 and size 0 mean.

The "data" is a text record with several numbers in two columns.

x = np.linspace(1735.0,1775.0,100)column1 = (data<0,0:-1>+data<0,1:>)/2.0column2 = data<1,1:>x_column1 = np.zeros(x.size+2)x_column1<1:-1> = xx_column1<0> = x<0>+x<0>-x<1>x_column1<-1> = x<-1>+x<-1>-x<-2>experiment = np.zeros_like(x)for i in range(np.size(x_edges)-2): indexes = np.flatnonzero(np.logical_and((column1>=x_column1),(column1
python numpy indexing error-handling index-error
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edited Feb 8 "19 at 22:17 user513951
asked jan 5 "17 in ~ 18:37 Seoyeon HongSeoyeon Hong
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In numpy, index and dimension number is numbered starts through 0. For this reason axis 0 means the 1st dimension. Likewise in numpy a measurement can have actually length (size) 0. The simplest instance is:

In <435>: x = np.zeros((0,), int)In <436>: xOut<436>: array(<>, dtype=int32)In <437>: x<0>...IndexError: index 0 is the end of bounds for axis 0 with dimension 0I additionally get it if x = np.zeros((0,5), int), a 2d variety with 0 rows, and also 5 columns.

You are watching: Indexerror: index 0 is out of bounds for axis 0 with size 0

So someplace in your password you room creating selection with a size 0 first axis.

When asking about errors, it is meant that girlfriend tell united state where the error occurs.

Also when debugging troubles like this, the very first thing you have to do is print the shape (and maybe the dtype) the the doubt variables.

## Applied to pandas

The same error can take place for those using pandas, once sending a series or DataFrame come a numpy.array, similar to the following:

## Resolving the error:

Use a try-except blockVerify the dimension of the variety is no 0if x.size != 0:
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edited jan 12 at 0:41 Trenton McKinney
answered january 5 "17 in ~ 19:02 hpauljhpaulj
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Essentially it way you don"t have actually the index you are trying come reference. Because that example:

df = pd.DataFrame()df<"this">=np.nandf<"my">=np.nandf<"data">=np.nandf<"data"><0>=5 #I haven"t yet assigned how long df must be!print(df)will give me the error you are referring to, since I haven"t said Pandas just how long my dataframe is. Whereas if I carry out the precise same code however I perform assign an index length, ns don"t get an error:

df = pd.DataFrame(index=<0,1,2,3,4>)df<"this">=np.nandf<"is">=np.nandf<"my">=np.nandf<"data">=np.nandf<"data"><0>=5 #since I"ve correctly labelled mine index, ns don"t run right into this problem!print(df)Hope that answers her question!

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reply Apr 27 "18 in ~ 21:29 Daniel AbudDaniel Abud