You are watching: Two teams of nine members each engage in a tug of war

## Calculator Screenshots

PreviousNext

Video Transcript

This is university Physics Answers v Shaun Dychko. We have two tug-o-war groups pulling top top a rope and team B is pulling to the right and there are nine people, every exerting a pressure of 1365 newtons because that a complete force the 12,285 newtons, and there room nine people there every weighing 73 kilograms for a full mass of 657 kilograms. Climate pulling the other method we have team A, each pulling with 1350 newtons, and each having a massive of 68 kilograms. So, our task is to figure out what the acceleration the this mechanism is going come be. So, the total mass the the device is the full mass that both teams put together. We have actually a net pressure of Fb come the right, minus Fa come the left, and the net force as constantly equals mass times acceleration. So due to the fact that F net equals this and also Fnet additionally equals that, we deserve to equate these two things which we perform here. For this reason mass times acceleration equates to Fb minus Fa and also then we"ll divide both political parties by m to gain the acceleration. Therefore it"s the force of team B minus the full force of team A, minus the complete mass of the two teams placed together. Therefore that"s 12,285 newtons minus 12,150 newtons, separated by 612 kilograms add to 657 kilograms, which renders 0.106 meter per 2nd squared. Then for component B, we"re request to discover the stress in the rope and we have the right to use among two various perspectives to figure that out. We could use the perspective I"ve drawn here where we have team A exerting a pressure to the left and also experiencing a pressure to the best equal come the anxiety force. We can have also drawn this photo F anxiety to the left and force the team B to the right, the would likewise have been fine since the pressure of anxiety is the same on every of the teams, the same magnitude anyhow, various directions. Us don"t require that there. So, the net pressure on team A which I"ve put a tiny apostrophe on it due to the fact that it isn"t the exact same net pressure as we were talking about up here. This net force is the net pressure in the whole system consist of of both teams together. This net pressure down here refers to the net force on just team A, and so team A experience a tension force to the appropriate minus the pressure that they"re exerting come the left, and also that"s going to same team A"s mass time its acceleration. Team A"s acceleration will be the exact same acceleration that we calculated in part A here. Therefore we"ll deal with for Ft by including Fa

1PE2PE3PE4PE5PE6PE7PE8PE9PE10PE11PE12PE13PE14PE15PE16PE17PE18PE19PE20PE21PE22PE23PE24PE25PE26PE27PE28PE29PE30PE31PE32PE33PE34PE35PE38PE39PE40PE41PE42PE43PE44PE45PE46PE47PE48PE49PE50PE51PE52PE53PE54PE

## Get the latest updates from college Physics Answers

Email resolve

Get updates

See more: How To Get Zygarde In Pokemon Y Garde, Catching Zygarde